Mishka arranged to play football with his
friends and was already about to leave home, but his mother stopped him. She
said that before he could go out to play, Mishka needed to help around the
house. His mother offered him a choice of one of three tasks: either wash the
dishes, vacuum the apartment, or play with his little sister Marinka while his
mom goes to the store. Mishka estimated how much time each task would take:
·
Washing
the dishes will take t1 seconds
·
Vacuuming
the apartment can be done in t2 seconds
·
Playing
with Marinka will take t3 seconds
It is clear that Mishka will choose the
task that takes the least time. Your program should determine and print this
minimum time.
Input. Three integers t1, t2, t3 (1 ≤ t1, t2, t3 ≤ 1000).
Output. Print the minimum time Mishka needs to complete his
mother’s task.
|
Sample
input |
Sample
output |
|
31 15 40 |
15 |
SOLUTION
conditional statement
Algorithm analysis
Mishka needs to choose the
task that will take the least time. In other words, it is required to calculate
the value of min(t1, t2, t3).
Algorithm implementation
Read the input data.
scanf("%d
%d %d",&t1,&t2,&t3);
Compute the minimum among t1, t2, t3.
min = t1;
if (t2 < min) min = t2;
if (t3 < min) min = t3;
Print the answer.
printf("%d\n",min);
Java implementation
import java.util.*;
public class Main
{
public static void main(String[] args)
{
Scanner con = new Scanner(System.in);
int a = con.nextInt();
int b = con.nextInt();
int c = con.nextInt();
int res = a;
if (b < res) res = b;
if (c < res) res = c;
System.out.println(res);
con.close();
}
}
Java implementation – Math.min
import java.util.*;
public class Main
{
public static void main(String[] args)
{
Scanner con = new Scanner(System.in);
int a = con.nextInt();
int b = con.nextInt();
int c = con.nextInt();
System.out.println(Math.min(Math.min(a,b),c));
con.close();
}
}
Python implementation
Read the input data.
t1, t2, t3 = map(int,input().split())
Compute the minimum among t1, t2, t3.
res = min(t1, t2, t3)
Print the answer.
print(res)